3.205 \(\int \sin ^3(a+b x) \sin ^n(c+d x) \, dx\)

Optimal. Leaf size=600 \[ \frac {2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (\frac {3 b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac {3\ 2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (\frac {b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {3\ 2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac {2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (-\frac {3 b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]

[Out]

2^(-3-n)*exp(I*(-c*n+3*a)+I*(-d*n+3*b)*x+I*n*(d*x+c))*(I/exp(I*(d*x+c))-I*exp(I*(d*x+c)))^n*hypergeom([-n, 3/2
*b/d-1/2*n],[1+3/2*b/d-1/2*n],exp(2*I*(d*x+c)))/((1-exp(2*I*c+2*I*d*x))^n)/(-d*n+3*b)-3*2^(-3-n)*exp(I*(-c*n+a
)+I*(-d*n+b)*x+I*n*(d*x+c))*(I/exp(I*(d*x+c))-I*exp(I*(d*x+c)))^n*hypergeom([-n, 1/2*(-d*n+b)/d],[1+1/2*b/d-1/
2*n],exp(2*I*(d*x+c)))/((1-exp(2*I*c+2*I*d*x))^n)/(-d*n+b)-3*2^(-3-n)*exp(-I*(c*n+a)-I*(d*n+b)*x+I*n*(d*x+c))*
(I/exp(I*(d*x+c))-I*exp(I*(d*x+c)))^n*hypergeom([-n, 1/2*(-d*n-b)/d],[1+1/2*(-d*n-b)/d],exp(2*I*(d*x+c)))/((1-
exp(2*I*c+2*I*d*x))^n)/(d*n+b)+2^(-3-n)*exp(-I*(c*n+3*a)-I*(d*n+3*b)*x+I*n*(d*x+c))*(I/exp(I*(d*x+c))-I*exp(I*
(d*x+c)))^n*hypergeom([-n, 1/2*(-d*n-3*b)/d],[1-3/2*b/d-1/2*n],exp(2*I*(d*x+c)))/((1-exp(2*I*c+2*I*d*x))^n)/(d
*n+3*b)

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Rubi [A]  time = 1.72, antiderivative size = 600, normalized size of antiderivative = 1.00, number of steps used = 18, number of rules used = 5, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {4553, 2285, 2253, 2252, 2251} \[ \frac {2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (\frac {3 b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac {3\ 2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (\frac {b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {3\ 2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac {2^{-n-3} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \left (1-e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (-\frac {3 b}{d}-n+2\right );e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]

Antiderivative was successfully verified.

[In]

Int[Sin[a + b*x]^3*Sin[c + d*x]^n,x]

[Out]

(2^(-3 - n)*E^(I*(3*a - c*n) + I*(3*b - d*n)*x + I*n*(c + d*x))*(I/E^(I*(c + d*x)) - I*E^(I*(c + d*x)))^n*Hype
rgeometric2F1[((3*b)/d - n)/2, -n, (2 + (3*b)/d - n)/2, E^((2*I)*(c + d*x))])/((1 - E^((2*I)*c + (2*I)*d*x))^n
*(3*b - d*n)) - (3*2^(-3 - n)*E^(I*(a - c*n) + I*(b - d*n)*x + I*n*(c + d*x))*(I/E^(I*(c + d*x)) - I*E^(I*(c +
d*x)))^n*Hypergeometric2F1[-n, (b - d*n)/(2*d), (2 + b/d - n)/2, E^((2*I)*(c + d*x))])/((1 - E^((2*I)*c + (2*
I)*d*x))^n*(b - d*n)) - (3*2^(-3 - n)*E^((-I)*(a + c*n) - I*(b + d*n)*x + I*n*(c + d*x))*(I/E^(I*(c + d*x)) -
I*E^(I*(c + d*x)))^n*Hypergeometric2F1[-n, -(b + d*n)/(2*d), 1 - (b + d*n)/(2*d), E^((2*I)*(c + d*x))])/((1 -
E^((2*I)*c + (2*I)*d*x))^n*(b + d*n)) + (2^(-3 - n)*E^((-I)*(3*a + c*n) - I*(3*b + d*n)*x + I*n*(c + d*x))*(I/
E^(I*(c + d*x)) - I*E^(I*(c + d*x)))^n*Hypergeometric2F1[-n, -(3*b + d*n)/(2*d), (2 - (3*b)/d - n)/2, E^((2*I)
*(c + d*x))])/((1 - E^((2*I)*c + (2*I)*d*x))^n*(3*b + d*n))

Rule 2251

Int[((a_) + (b_.)*(F_)^((e_.)*((c_.) + (d_.)*(x_))))^(p_)*(G_)^((h_.)*((f_.) + (g_.)*(x_))), x_Symbol] :> Simp
[(a^p*G^(h*(f + g*x))*Hypergeometric2F1[-p, (g*h*Log[G])/(d*e*Log[F]), (g*h*Log[G])/(d*e*Log[F]) + 1, Simplify
[-((b*F^(e*(c + d*x)))/a)]])/(g*h*Log[G]), x] /; FreeQ[{F, G, a, b, c, d, e, f, g, h, p}, x] && (ILtQ[p, 0] ||
GtQ[a, 0])

Rule 2252

Int[((a_) + (b_.)*(F_)^((e_.)*((c_.) + (d_.)*(x_))))^(p_)*(G_)^((h_.)*((f_.) + (g_.)*(x_))), x_Symbol] :> Dist
[(a + b*F^(e*(c + d*x)))^p/(1 + (b/a)*F^(e*(c + d*x)))^p, Int[G^(h*(f + g*x))*(1 + (b*F^(e*(c + d*x)))/a)^p, x
], x] /; FreeQ[{F, G, a, b, c, d, e, f, g, h, p}, x] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rule 2253

Int[((a_) + (b_.)*(F_)^((e_.)*(v_)))^(p_)*(G_)^((h_.)*(u_)), x_Symbol] :> Int[G^(h*ExpandToSum[u, x])*(a + b*F
^(e*ExpandToSum[v, x]))^p, x] /; FreeQ[{F, G, a, b, e, h, p}, x] && LinearQ[{u, v}, x] &&  !LinearMatchQ[{u, v
}, x]

Rule 2285

Int[(u_.)*((a_.)*(F_)^(v_) + (b_.)*(F_)^(w_))^(n_), x_Symbol] :> Dist[(a*F^v + b*F^w)^n/(F^(n*v)*(a + b*F^Expa
ndToSum[w - v, x])^n), Int[u*F^(n*v)*(a + b*F^ExpandToSum[w - v, x])^n, x], x] /; FreeQ[{F, a, b, n}, x] &&  !
IntegerQ[n] && LinearQ[{v, w}, x]

Rule 4553

Int[Sin[(a_.) + (b_.)*(x_)]^(p_.)*Sin[(c_.) + (d_.)*(x_)]^(q_.), x_Symbol] :> Dist[1/2^(p + q), Int[ExpandInte
grand[(I/E^(I*(c + d*x)) - I*E^(I*(c + d*x)))^q, (I/E^(I*(a + b*x)) - I*E^(I*(a + b*x)))^p, x], x], x] /; Free
Q[{a, b, c, d, q}, x] && IGtQ[p, 0] &&  !IntegerQ[q]

Rubi steps

\begin {align*} \int \sin ^3(a+b x) \sin ^n(c+d x) \, dx &=2^{-3-n} \int \left (3 i e^{-i a-i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n-3 i e^{i a+i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n-i e^{-3 i a-3 i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n+i e^{3 i a+3 i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \, dx\\ &=-\left (\left (i 2^{-3-n}\right ) \int e^{-3 i a-3 i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, dx\right )+\left (i 2^{-3-n}\right ) \int e^{3 i a+3 i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, dx+\left (3 i 2^{-3-n}\right ) \int e^{-i a-i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, dx-\left (3 i 2^{-3-n}\right ) \int e^{i a+i b x} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, dx\\ &=-\left (\left (i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-3 i a-3 i b x-i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx\right )+\left (i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{3 i a+3 i b x-i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-i a-i b x-i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{i a+i b x-i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx\\ &=\left (i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{i (3 a-c n)+i (3 b-d n) x} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx-\left (i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-i (3 a+c n)-i (3 b+d n) x} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{i (a-c n)+i (b-d n) x} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (i-i e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-i (a+c n)-i (b+d n) x} \left (i-i e^{2 i c+2 i d x}\right )^n \, dx\\ &=\left (i 2^{-3-n} e^{i n (c+d x)} \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{i (3 a-c n)+i (3 b-d n) x} \left (1-e^{2 i c+2 i d x}\right )^n \, dx-\left (i 2^{-3-n} e^{i n (c+d x)} \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-i (3 a+c n)-i (3 b+d n) x} \left (1-e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{i (a-c n)+i (b-d n) x} \left (1-e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n\right ) \int e^{-i (a+c n)-i (b+d n) x} \left (1-e^{2 i c+2 i d x}\right )^n \, dx\\ &=\frac {2^{-3-n} \exp (i (3 a-c n)+i (3 b-d n) x+i n (c+d x)) \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (2+\frac {3 b}{d}-n\right );e^{2 i (c+d x)}\right )}{3 b-d n}-\frac {3\ 2^{-3-n} \exp (i (a-c n)+i (b-d n) x+i n (c+d x)) \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (2+\frac {b}{d}-n\right );e^{2 i (c+d x)}\right )}{b-d n}-\frac {3\ 2^{-3-n} \exp (-i (a+c n)-i (b+d n) x+i n (c+d x)) \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};e^{2 i (c+d x)}\right )}{b+d n}+\frac {2^{-3-n} \exp (-i (3 a+c n)-i (3 b+d n) x+i n (c+d x)) \left (1-e^{2 i c+2 i d x}\right )^{-n} \left (i e^{-i (c+d x)}-i e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (2-\frac {3 b}{d}-n\right );e^{2 i (c+d x)}\right )}{3 b+d n}\\ \end {align*}

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Mathematica [F]  time = 0.58, size = 0, normalized size = 0.00 \[ \int \sin ^3(a+b x) \sin ^n(c+d x) \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[Sin[a + b*x]^3*Sin[c + d*x]^n,x]

[Out]

Integrate[Sin[a + b*x]^3*Sin[c + d*x]^n, x]

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fricas [F]  time = 0.66, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-{\left (\cos \left (b x + a\right )^{2} - 1\right )} \sin \left (d x + c\right )^{n} \sin \left (b x + a\right ), x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c)^n,x, algorithm="fricas")

[Out]

integral(-(cos(b*x + a)^2 - 1)*sin(d*x + c)^n*sin(b*x + a), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sin \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c)^n,x, algorithm="giac")

[Out]

integrate(sin(d*x + c)^n*sin(b*x + a)^3, x)

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maple [F]  time = 6.42, size = 0, normalized size = 0.00 \[ \int \left (\sin ^{3}\left (b x +a \right )\right ) \left (\sin ^{n}\left (d x +c \right )\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(b*x+a)^3*sin(d*x+c)^n,x)

[Out]

int(sin(b*x+a)^3*sin(d*x+c)^n,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sin \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c)^n,x, algorithm="maxima")

[Out]

integrate(sin(d*x + c)^n*sin(b*x + a)^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\sin \left (a+b\,x\right )}^3\,{\sin \left (c+d\,x\right )}^n \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(a + b*x)^3*sin(c + d*x)^n,x)

[Out]

int(sin(a + b*x)^3*sin(c + d*x)^n, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)**3*sin(d*x+c)**n,x)

[Out]

Timed out

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